Here is a new topic I bring to you. It’s about math, I mean, paradoxical math. Can all maths be 100% true without any possible loopholes? Or does it have some mistakes that cannot be explained logically? One way to find out, check this one out!

## 3 thoughts on “Math Paradox???”

1. វិចិត្រ ថា:

សូម​ពិនិត្យ

$\sqrt{-1} \times \sqrt{-1}$ ​ស្មើ​នឹង​ $\left (\sqrt{-1} \right )^2$ តែ​មិន​ស្មើ​នឹង​ $\sqrt{(-1)^2}$

2. វិចិត្រ ថា:

សូម​ពិនិត្យ
$\sqrt{-1} \times \sqrt{-1}$ ​ស្មើ​នឹង​ $\left (\sqrt{-1} \right )^2$ តែ​មិន​ស្មើ​នឹង​ $\sqrt{(-1)^2}$

3. I should explain it like this. In fact, the 6th-root of 1 has 6 solutions, 4 are complex numbers (in the form of real part+imaginary part) and 2 are real numbers (that is 1 and -1) so 6th-root of 1 can be 1 or -1 or the other 4 but among the 6 number the equality doesn’t exist.